InvertPermutation

tensorflow C++ API

tensorflow::ops::InvertPermutation

Computes the inverse permutation of a tensor.

Summary

This operation computes the inverse of an index permutation. It takes a 1-D integer tensorx, which represents the indices of a zero-based array, and swaps each value with its index position. In other words, for an output tensoryand an input tensorx, this operation computes the following:

y[x[i]] = i for i in [0, 1, ..., len(x) - 1]

The values must include 0. There can be no duplicate values or negative values.

For example:

```
tensorx` is [3, 4, 0, 2, 1]

invert_permutation(x) ==> [2, 4, 3, 0, 1]
```

Arguments:

• scope: A Scope object
• x: A Tensor. Must be one of the following types: int32, int64. 1-D.

Returns:

• Output: A Tensor. Has the same type as x . 1-D.

InvertPermutation block

Source link :https://github.com/EXPNUNI/enuSpaceTensorflow/blob/master/enuSpaceTensorflow/tf_array_ops.cpp

Argument:

• Scope scope : A Scope object (A scope is generated automatically each page. A scope is not connected.)
• Input x : A 1-D Tensor type of int32,int64(Must be one integer type).

Output:

• y : Output object of InvertPermutation class object.

Result:

• std::vector(Tensor) result_y: A Tensor . invert x and y (x <--> y)

Using Method

• X에 들어있는 값과 인덱스를 서로 바꾸어서 표현한다. x = [1, 4, 3, 0, 2] --> y = [3, 0, 4, 2, 1]. 인덱스: x = [0, 1, 2, 3, 4] y = [0, 1, 2, 3, 4]